add dict function for services by cloud_env #46

Merged
sgode merged 1 commits from add_dict_function into main 2025-08-13 13:45:18 +00:00

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@ -475,3 +475,33 @@ class Services(object):
res.sort(key=lambda x: x.get("service_title", "").lower())
return res
def all_services_by_cloud_environment_as_dict(self, cloud_environment, environments):
"""Retrieve all services filtered by cloud_environment
Returns a dict keyed by service_type.
"""
res = {}
if not (environments and cloud_environment):
raise Exception(
"No cloud_environment or environments specified in function all_services_by_cloud_environment."
)
for srv in self.all_services:
for srv_cloud_environment in srv.get("cloud_environments", []):
if srv_cloud_environment.get("name") == cloud_environment:
for environment in environments:
if srv_cloud_environment.get("visibility") == environment:
service_type = srv.get("service_type")
if service_type:
res[service_type] = srv
break
res = dict(
sorted(
res.items(),
key=lambda item: item[1].get("service_type", "").lower()
)
)
return res